Correct answer: B. Ea/RT K Ae  Ea = Threshold energy – energy of reactant = 90.5 logK = logA– Ea

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AITS & Test SerieshardMCQ SINGLE

Question

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Answer: B

💡 Solution & Explanation

Ea/RT K Ae  Ea = Threshold energy – energy of reactant = 90.5 logK = logA– Ea

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