600 mL of 0.0 1M HCl is mixed with 400 mL of 0.01 M H2SO4. The pH of the mixture is _____ . × 10–2. — JEE Mains Chemistry Past Papers Chemistry Question

💡 Solution & Explanation

HCl  H+ + Cl– Milli moles 0.01×600 H2SO4  2H+ + SO4 –2 Milli moles 0.01×400 2×4=8 [H+] = 6 8  = 14 × 10–3 pH = –log(14 × 10–3) = 3 – log14 = 3 – log(2 × 7) = 3 – log2 – log7 = 3 – 0.30 – 0.84 = 1.86 = 186 × 10–2 | JEE(Main) 2023 | DATE : 30-01-2023 (SHIFT-1) | PAPER-1 | OFFICIAL PAPER | CHEMISTRY PAGE # 10