See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Complexes Number of geometrical isomers (I)    3 2 2 Pt NH SCN     2 (II)    3 2 3 3 Co NH NO     2 (III)   2 Pt en Cl     0 (IV)   2 2 Cr en Br      2 (V)   3 3 Rh en      0 (VI)   2 2 2 CoCl Br  0 Hence, sum of total number of geometrical isomers = 6.