[Single-digit Integer] The density of graphite is 2.4 g/ml and the spacing between the layers is found by X-ray diffraction to be 2 * sqrt(3) A. If the carbon-carbon distance in the molecular layers i

Question

[Single-digit Integer] The density of graphite is 2.4 g/ml and the spacing between the layers is found by X-ray diffraction to be 2 * sqrt(3) A. If the carbon-carbon distance in the molecular layers is x A, then the value of 1.08 * x^2 is

Prashant Kotian · Accepted Answer

Correct answer: 2. In graphite, the volume of a hexagonal unit cell is V = Area of base * height = (3 * sqrt(3) * x^2) * d_spacing = 3 * sqrt(3) * x^2 * (2 * sqrt(3) * 10^-8 cm) = 18 * x^2 * 10^-24 cm3. A unit cell contains 4 carbon atoms. Density ρ = (Z * M) / (Na * V) => 2.4 = (4 * 12) / (6 * 10^23 * 18 * x^2 * 10^-24) = 48 / (1.08 * x^2) => 1.08 * x^2 = 48 / 24 = 2. Thus, the value is 2.

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