See image — GOC and Organic Chemistry Basics Chemistry Question

💡 Solution & Explanation

Concept: Reaction of sodium with methyl alcohol (methanol, CH3OH). The balanced chemical equation is: 2 Na + 2 CH3OH → 2 CH3ONa + H2 Step 1: Determine moles of sodium. Molar mass of Na = 23 g/mol Moles of Na = 23 g / 23 g/mol = 1 mole of Na Step 2: Use stoichiometry to find moles of H2 produced. From the balanced equation: 2 moles of Na produce 1 mole of H2. Therefore, 1 mole of Na produces 1/2 mole of H2. Step 3: Convert moles of H2 to volume at NTP. At NTP (0°C and 1 atm), 1 mole of any gas occupies 22.4 L. Volume of H2 = 0.5 mol × 22.4 L/mol = 11.2 L Why other options fail: (a) Oxygen is not a product of this reaction; sodium reacts with methanol to give sodium methoxide and hydrogen gas. (b) 22.4 dm^3 would correspond to 1 mole of H2, but only 0.5 mole is produced. (c) 1 mole of H2 would require 2 moles of Na (46 g), but we only have 1 mole (23 g) of Na. (d) 11.2 L = 0.5 mole × 22.4 L/mol, which correctly corresponds to 0.5 mole of H2 produced from 1 mole of Na. Therefore, the correct answer is D.