The speed of electron revolving in the fourth orbit of a hydrogen-like atom or ion is 1094 km/s. The β Atomic Structure Chemistry Question
Question
The speed of electron revolving in the fourth orbit of a hydrogen-like atom or ion is 1094 km/s. The atom or ion is
Answer: B
π‘ Solution & Explanation
v = 2188*Z/n km/s. For n=4: 1094 = 2188*Z/4 => Z = 2, which is He^+.
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