See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Sol. Let aqueous V. P. be p mm of Hg Initial conditions NTP conditions 1 P (dry gas) = (750p) mm 2 P = 760 mm 1 V = 100 mL 2 V =91.9 mL 1 T = 15 + 273 = 288 K 1 T = 273 K 1 1 2 2 1 2 P V P V , T T    750 p 760 91.9 100 288 273     (750 p) = 736.8 P = 13.2 mm