JEE Mains Chemistry Past PapershardNUMERICAL

Standard entropies of X2, Y2 and XY5 are 70, 50 and 110 J K–1 mol–1 respectively. The temperature inJEE Mains Chemistry Past Papers Chemistry Question

Question

Standard entropies of X2, Y2 and XY5 are 70, 50 and 110 J K–1 mol–1 respectively. The temperature in Kelvin at which the reaction. 1 X2 + 2 5 Y2 XY5 H = –35kJ mol–1 will be at equilibrium is _________ (Nearest integer)

Answer: .

💡 Solution & Explanation

S = 110 –          2 70 1 = –50 J At eq., G = 0 H = TS  T = 35000   = 700 K

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