Correct answer: B. pOH = pKb + log   4 3 NH b NH pK        (OH) = 1.8105 Ksp = [Mn2+] [OH]2, [Mn2+] = 1.38104

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AITS & Test SerieshardMCQ SINGLE

Question

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Answer: B

💡 Solution & Explanation

pOH = pKb + log   4 3 NH b NH pK        (OH) = 1.8105 Ksp = [Mn2+] [OH]2, [Mn2+] = 1.38104

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