The RMS speed of a sample of ozone is 'v' m/s at 27Β°C. When the temperature is increased to 327Β°C, a β States of Matter and Gaseous State Chemistry Question
Question
The RMS speed of a sample of ozone is 'v' m/s at 27Β°C. When the temperature is increased to 327Β°C, all the ozone molecules are dissociated into oxygen molecules. What is the RMS speed of new gas sample?
Answer: D
π‘ Solution & Explanation
ozone (m1 = 48) at t1 = 300 k has rms speed v = β(3r Γ 300 / 48). oxygen molecules (m2 = 32) at t2 = 600 k have rms speed u2 = β(3r Γ 600 / 32). ratio: u2 / v = β(600 / 300 Γ 48 / 32) = β(2 Γ 1.5) = β3. thus, u2 = β3 v.
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