Graph between log(x/m) and log P is a straight line at an angle 45 degrees with intercept on y-axis, 0.3010. The amount (in g) of the gas absorbed per g of the adsorbent when pressure is 0.2 atm, is (

Question

Graph between log(x/m) and log P is a straight line at an angle 45 degrees with intercept on y-axis, 0.3010. The amount (in g) of the gas absorbed per g of the adsorbent when pressure is 0.2 atm, is (assume that the adsorption obey Freundlich isotherm)

Prashant Kotian · Accepted Answer

Correct answer: A. From Freundlich isotherm, log(x/m) = log k + (1/n)log P. Here, slope (1/n) = tan(45 degrees) = 1. Intercept (log k) = 0.3010 => k = 2. When pressure P = 0.2 atm, x/m = k * P^(1/n) = 2 * (0.2)^1 = 0.4 g of gas per g of adsorbent.

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