A crystal is made up of metal ions 'M1' and 'M2' and oxide ions. Oxide ions form a ccp lattice struc — JEE Mains Chemistry Past Papers Chemistry Question
Question
A crystal is made up of metal ions 'M1' and 'M2' and oxide ions. Oxide ions form a ccp lattice structure. The cation 'M1' occupies 50% of octahedral voids and the cation 'M2' occupies 12.5% of tetrahedral voids of oxide lattice. The oxidation numbers of 'M1' and 'M2' are, respectively: (A) + 1, +3 (B) +3, +1 (C) +2, +4 (D) +4, +2
Answer: C
💡 Solution & Explanation
In the ccp lattice of oxide ions effective number of O–2 ions = 8 × 8 1 + 6 × 2 1 = 4 In the ccp lattice, No. of octahedral voids = 4 No. of tetrahedral voids = 8 Given M1 atoms occupies 50% of octahedral voids and M2 atoms occupies 12.5 of tetrahedral voids No. of M1 metal atoms = 4 × 100 50 = 2 No. of M2 metal atoms = 8 ×
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