When is allowed to react with following Lewis bases, then how many given Lewis bases form adduct through symmetrical cleavage of ?

Question

When $B_2H_6$ is allowed to react with following Lewis bases, then how many given Lewis bases form adduct through symmetrical cleavage of $B_2H_6$?
$NH_3, MeNH_2, ext{Pyridine}, CO, T.H.F., PH_3, PF_3, Me_3N, Me_2NH$

Prashant Kotian · Accepted Answer

Correct answer: 6

**SOLUTION:** SYMMETRICAL CLEAVAGE OF $B_2H_6$ OCCURS WITH LARGE SIZED STRONG LEWIS BASES OR WEAKER LEWIS BASES LIKE: $PH_3, PF_3, CO, T.H.F., ME_3N, \TEXT{PYRIDINE}$. TOTAL = 6.. Step 1: Analyze the geometries of the given species. NCO^- is linear (sp hybridized central carbon). CS2 is linear (sp hybridized central carbon, analogous to CO2). NO2^+ is linear (sp hybridized nitrogen, with 0 lone pairs). Step 2: For BeH2, in the gaseous state, monomeric BeH2 is linear. However, in the solid state, BeH2 polymerizes via 3-center-2-electron Be-H-Be bridge bonds into a tetrahedral network (non-linear chain). Step 3: Thus, only NCO^-, CS2, and NO2^+ assume a linear structure, making (c) the correct option.

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