If heat of solution for AB(s) is -0.95 x 10^x kcal/mol and lattice energy for AB(s) is 700 kcal/mol and hydration energy for A+(g) is -1000 kcal/mol and B-(g) is -650 kcal/mol then calculate value of

Question

If heat of solution for AB(s) is -0.95 x 10^x kcal/mol and lattice energy for AB(s) is 700 kcal/mol and hydration energy for A+(g) is -1000 kcal/mol and B-(g) is -650 kcal/mol then calculate value of x.

Prashant Kotian · Accepted Answer

Correct answer: 3. Step 1: Understand that electropositive character (metallic character) increases moving down a group and decreases moving from left to right across a period. Step 2: Alkali metals (Group 1) are always more electropositive than alkaline earth metals (Group 2) within the same period due to lower ionization energies. Step 3: Among the choices, [He] 2s1 (Lithium) and [Xe] 6s1 (Cesium) are alkali metals. Since Cesium is much further down Group 1 than Lithium, its outermost electron is most easily lost, making [Xe] 6s1 the configuration of the most electropositive element.

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