Observe the following reactions at T(K) I. A → products. II. 5Br – (aq) + BrO3 – (aq) + 6H +(aq) → 3Br2(aq) + 3H2O(l) Both the reactions are started at 10.00 am. The rates of these reactions at 10.10

Question

Observe the following reactions at T(K) I. A → products. II. 5Br – (aq) + BrO3 – (aq) + 6H +(aq) → 3Br2(aq) + 3H2O(l) Both the reactions are started at 10.00 am. The rates of these reactions at 10.10 am are same. The value of [Br ] t at 10.10 am is 2 × 10 –4 mol L –1 Min –1. The concentration of A at 10.10 am is 10 –2 mol L –1. What is the first order rate constant (in min –1) of reaction I?

(A) 2 × 10 –3
(B) 10 –3
(C) 10 –2
(D) 4 × 10 –3 ALLEN

Prashant Kotian · Accepted Answer

Correct answer: D. At t = 10 minutes Rate of reaction = – 1 [Br ] t    = 1 5 × (2 × 10 –4) = 4 × 10 –5 For reaction A  P at t = 10 minutes Rate of reaction = 4 × 10 –5 = k[A] k = 4 × 10 –3 min –1.

💡 Solution & Explanation

Practice 22,000+ questions like this