In the reversible adiabatic expansion of an ideal monoatomic gas, the final volume is 8 times the in — Thermodynamics and Thermochemistry Chemistry Question

💡 Solution & Explanation

For a reversible adiabatic process of an ideal gas: T * V^(γ - 1) = constant. For a monoatomic gas, γ = 5/3, so γ - 1 = 2/3. T2/T1 = (V1/V2)^(2/3) = (1/8)^(2/3) = 1/4. Thus, the ratio of final to initial temperature is 1:4.