Ratio of maximum to minimum photocurrent which can be passed through the circuit is — Atomic Structure Chemistry Question

💡 Solution & Explanation

Maximum photocurrent when all three guns are capable: pairing P=5W with n=9×10^18 (E_p=5.56×10^-19 J > φ), P=3W with n=5×10^18 (E_p=6.0×10^-19 J > φ), P=2W with n=4×10^18 (E_p=5.0×10^-19 J > φ). All three emit: n_total = (4+5+9)×10^18 = 18×10^18 s^-1. I_max / I_min = 18×10^18 / 4×10^18 = 9:2.