See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

(I) 1 2 1 2 x x 2m, x x m    then 3 2 3 2 8m 3m(2m) 4m 2m 8m 10m 2m 0 1 m 0, m 1, m 4           (II) p 4, 2   (III) Let a b x c d       1 1 then d b ,a b,c 2b 2b 2b 1 1 Also, b , or b 6 2        (IV) det   2 2 1 A B 12 A BC C 5    .