Cu | Cu2 E = +0.34 V Zn | Zn2 E = –0.76 V Identify the incorrect statement from the options below for the above cell : (A) If Eext = 1.1 V, no flow of e– or current occurs (B) If Eext

Question

Cu | Cu2 E = +0.34 V Zn | Zn2 E = –0.76 V Identify the incorrect statement from the options below for the above cell :

(A) If Eext = 1.1 V, no flow of e– or current occurs
(B) If Eext < 1.1 V, Zn dissolves at anode and Cu deposits at cathode
(C) If Eext > 1.1 V, e– flow from Cu to Zn
(D) If Eext > 1.1 V, Zn dissolves at Zn electrode and Cu deposits at Cu electrode

Prashant Kotian · Accepted Answer

Correct answer: D. º Cu | Cu º cell E E   – º Zn | Zn2 E  = 1.1 V so If E = 1.1 V no electron will flow At E > 1.1 V cell act as electrolytic cell and electron will flow from Cu to Zn. At E < 1.1 V cell act as electrochemical cell so Zn dissolve and Cu deposit.

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