See image — IUPAC and Nomenclature Chemistry Question

💡 Solution & Explanation

Step 1 – Identify the parent structure. The molecule contains a benzene ring with two substituents, so we treat it as a phenyl ketone (aryl ketone). The carbonyl carbon bears the benzene ring on one side and a five-carbon chain (pentyl) on the other, making the longest carbon chain including the carbonyl six carbons total: hexan-1-one. Step 2 – Name the acyl/ketone portion. The carbonyl is at C-1 of a six-carbon chain (C=O + 5 CH2/CH3 carbons = hexan-1-one), so the ketone fragment is hexan-1-one. Step 3 – Name the aryl substituent. The phenyl ring carries a bromine atom. Numbering the ring so that C-1 bears the carbonyl group, the bromine is located at C-3 (meta position), giving 3-bromophenyl. Step 4 – Assemble the IUPAC name. The aryl group is named as a substituent on the ketone: 1-(3-bromophenyl)hexan-1-one. The '1-' prefix before the parenthesis locates the aryl group at C-1, and 'hexan-1-one' specifies the six-carbon chain with the ketone at C-1. No other regiochemical assignments are possible because the bromine is clearly at the meta (3-) position relative to the carbonyl-bearing carbon. Therefore, the correct answer is 1-(3-bromophenyl)hexan-1-one.