The equation of state for a van der Waal gas can be expressed as Z = 1 + B/Vm + C/Vm^2 + ... If the van der Waal constants a and b are 1.344 litre^2 atm/mol^2 and 0.03 litre mol^-1, respectively, then

Question

The equation of state for a van der Waal gas can be expressed as Z = 1 + B/Vm + C/Vm^2 + ... If the van der Waal constants a and b are 1.344 litre^2 atm/mol^2 and 0.03 litre mol^-1, respectively, then the value of second virial coefficient (in litre/mol) for oxygen gas at 0°C is

Prashant Kotian · Accepted Answer

Correct answer: A. the second virial coefficient b in the virial equation of state is b = b - a / (rt). given a = 1.344 l^2 atm/mol^2, b = 0.03 l/mol, t = 273 k, and r = 0.0821 l atm/(k mol). b = 0.03 - 1.344 / (0.0821 × 273) = 0.03 - 1.344 / 22.4 = 0.03 - 0.06 = -0.03.

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