An aqueous solution of 'X' is added slowly to an aqueous solution of 'Y'. The variation in conductiv β Electrochemistry Chemistry Question
Question
An aqueous solution of 'X' is added slowly to an aqueous solution of 'Y'. The variation in conductivity is shown in Column II. Column I: (A) $(\text{C}_2\text{H}_5)_3\text{N}$ added to $\text{CH}_3\text{COOH}$ (B) $\text{KI}\ (0.1\ \text{M})$ added to $\text{AgNO}_3\ (0.01\ \text{M})$ (C) $\text{CH}_3\text{COOH}$ added to $\text{KOH}$ (D) $\text{NaOH}$ added to $\text{HI}$. Column II: (P) Conductivity decreases then increases (Q) Conductivity decreases then does not change much (R) Conductivity increases then does not change much (S) Conductivity does not change much then increases
π‘ Solution & Explanation
\textbf{Match the Following β Conductometric Titration Curves} \textbf{Column I (Titration type)} \quad \textbf{Column II (Conductance vs volume curve)} \textbf{Analysis:} \textbf{A. Strong acid vs Strong base (HCl + NaOH):} Conductance decreases as H\textsuperscript{+} (high mobility) is replaced by Na\textsuperscript{+}. At equivalence point, conductance is minimum (only NaCl). After equivalence, conductance rises as excess OH\textsuperscript{-} is added. Shape: V-shaped with minimum at equivalence point \quad β \textbf{R} \textbf{B. Weak acid vs Strong base (CH\textsubscript{3}COOH + NaOH):} Initially very low conductance (weak acid barely ionised). As NaOH is added, salt (CH\textsubscript{3}COONa) forms β conductance rises slowly. After equivalence, excess NaOH causes sharp rise. Shape: nearly flat then steep rise after equivalence \quad β \textbf{S} \textbf{C. Strong acid vs Weak base (HCl + NH\textsubscript{4}OH):} Conductance decreases as mobile H\textsuperscript{+} is replaced by NH\textsubscript{4}\textsuperscript{+} (less mobile). After equivalence, adding more NH\textsubscript{4}OH (weak base) causes very slight change (barely ionised). Shape: decreasing then nearly flat after equivalence \quad β \textbf{Q} \textbf{D. Weak acid vs Weak base (CH\textsubscript{3}COOH + NH\textsubscript{4}OH):} Both are poorly ionised. Conductance changes are very small throughout. The curve is nearly flat with a poorly defined minimum. Shape: nearly flat throughout \quad β \textbf{P} \textbf{Answer: AβR; BβS; CβQ; DβP}