Based on the data given below: o Cr / O Cr 2 2 E = 1.33 V o Cl / Cl – E = 1.36 V o Mn / MnO 4 E = 1. — JEE Mains Chemistry Past Papers Chemistry Question
Question
Based on the data given below: o Cr / O Cr 2 2 E = 1.33 V o Cl / Cl – E = 1.36 V o Mn / MnO 4 E = 1.51 V o Cr / Cr3 E = –0.74 V the strongest reducing agent is: (A) MnO (B) Cr (C) Mn2+ (D) Cl–
Answer: B
💡 Solution & Explanation
Species written on RHS of least SRP electrode is best RA (here, Cr).
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