JEE Mains Chemistry Past PapershardNUMERICAL

An empty LPG cylinder weighs 14.8 kg. When full, it weighs 29.0 kg and shows a pressure of 3.47 atm.JEE Mains Chemistry Past Papers Chemistry Question

Question

An empty LPG cylinder weighs 14.8 kg. When full, it weighs 29.0 kg and shows a pressure of 3.47 atm. In the course of use at ambient temperature, the mass of the cylinder is reduced to 23.0 kg. The final pressure inside the cylinder is __________ atm. (Nearest integer) (Assume LPG to be an ideal gas) ,d [kkyh LPG flfyaMj dk Hkkj 14.8 kg gSA iwjk Hkkj gks us ij bldk Hkkj 29.0 kg gS ,oa ;g 3.47 atm nkc iznf'kZr djrk gSA ifjos'k rki ij bLrseky fd, tkus ds nkSjku flfyaMj dk nzO;eku ?kV dj 23.0 kg jg tkrk gSA flfyaMj ds vanj vafre nkc gS __________ atm. (fudVre iw.kk±d esa) (LPG dks ,d vkn'kZ xSl ekusa)

Answer: .

💡 Solution & Explanation

Initial mass of gas = 29 –14.8 = 14.2 Kg mass of gas used = 29 –23 = 6 Kg gas left = 14.2 – 6 = 8.2 Kg (1) 3.47 × V =          M 2 . 3 × R × T (2) p × V =          M 2 . 3 × R × T Divide : (1) / (2)  P . = . 2 . P = 2.003 | JEE MAIN-2021 | DATE : 01-09-2021 (SHIFT-2) | PAPER-1 | OFFICAL PAER | CHEMISTRY PAGE # 8

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