See image — IUPAC and Nomenclature Chemistry Question

💡 Solution & Explanation

Step 1 - Identify the parent ring: The structure shows a six-membered carbocyclic ring (cyclohexane). Step 2 - Identify all substituents and features on the ring: (a) An exocyclic double bond (=CH2, methylidene group) on one carbon, making that carbon sp2. (b) A bromine (Br) on the carbon adjacent to the methylidene carbon. (c) A hydroxyl group (OH) on the next carbon. (d) A chlorine (Cl) on the carbon adjacent to the OH carbon. Step 3 - Number the ring to give lowest locants. The OH group defines the cyclohexanol parent. Assign C1 to the carbon bearing OH. Going in the direction that gives lower locants: C1 = OH, C2 = Br, C3 = exocyclic =CH2 (methylidene), C6 = Cl. Step 4 - Construct the IUPAC name: Parent = cyclohexanol. Substituents: 2-bromo, 6-chloro, 3-methylidene (exocyclic =CH2 at C3). Full name: 2-bromo-6-chloro-3-methylidenecyclohexanol. Step 5 - Verify against the image: The ring has Cl at the top carbon, OH on the adjacent carbon to Cl, Br on the next carbon, and =CH2 (exocyclic methylene drawn as a terminal alkene) on the carbon adjacent to Br. This matches 2-bromo-6-chloro-3-methylidenecyclohexanol exactly. No other connectivity arrangement is consistent with the drawn structure. Therefore, the correct answer is 2-bromo-6-chloro-3-methylidene-cyclohexanol.