Find the emf of the cell in which the following reaction takes place at 298 K Mg(s) + 2Ag (0.001 M) — NEET Chemistry Past Papers Chemistry Question

Question

Find the emf of the cell in which the following reaction takes place at 298 K Mg(s) + 2Ag (0.001 M) → Mg (0.01 M) + 2Ag(s) (Given that at 298 K) (A) 3.17 V (B) 3.052 V (C) 2.14 V (D) 3.52 V + 2+ Eo cell = 3.17V , = 0.059 2.303RT F Mg(s) + 2Ag (0.001 M) → Mg (0.01 M) + 2Ag(s) ) (1) 3.17 V (2) 3.052 V (3) 2.14 V (4) 3.52 V + 2+ Eo cell = 3.17V , = 0.059 2.303RT F