AITS & Test SerieshardNUMERICAL

See imageAITS & Test Series Chemistry Question

Question

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Answer: 3

💡 Solution & Explanation

Using LMVT, 1 1 2 tan tan 1 1 c       Where 0 << c <3 So, 2 1 1 1 4 1 c    So, 1 1 1 4 tan tan        So the answer is 3

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