See image — AITS & Test Series Chemistry Question
Question
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Answer: C
💡 Solution & Explanation
AgBr=x+y K×1000 AgBr= M M – molarity of AgBr solution 8 (solubility in g/L) = K×1000×188 x+y AITS-CRT-I-PCM(Sol.)-JEE(Main)/22 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 7
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