Three solutions of strong electrolytes, 25 ml of 0.1 M - HX, 25 ml of 0.1 M - H2Y and 50 ml of 0.1 N - Z(OH)2 are mixed. pOH of the resulting solution is

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Question

Prashant Kotian · Accepted Answer

Correct answer: C. H+ from HX = 2.5 meq. H+ from H2Y = 5.0 meq. Total H+ = 7.5 meq. OH- from Z(OH)2 = 5.0 meq. Excess H+ = 2.5 meq in 100 mL. [H+] = 0.025 M. pH = 1.6. pOH = 14 - 1.6 = 12.4.

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