See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

   2 n CH C CH C CH A    3 2 2 BH / H O ,OH   2 addition of H O followed by tautomerisation    2 2 2 n OHC CH CH CH CHO B     Molar mass of A = (14n + 50) Molar mass of B = (14n + 86)