See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

O3  2 3 O 2 K = 5  10–4     2 3 4 8 1 1 d O 5 10 2 10 mol L s dt         =   2 4 8 23 1 5 10 2 10 6 10 60 1000          = 7200 molecules mL–1 min–1 For More Material Join: @JEEAdvanced_2024 AITS-CRT-I (Paper-1)-PCM(Sol.)-JEE(Advanced)/2023 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 10 Mathematics PART – III Section – A