Correct answer: 3. 1 Xe Xe 1e , I.E 1170 kJmol       1 2 2 O O 1e , I.E 1175 kJ mol      

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AITS & Test SerieshardNUMERICAL

Question

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Answer: 3

💡 Solution & Explanation

1 Xe Xe 1e , I.E 1170 kJmol       1 2 2 O O 1e , I.E 1175 kJ mol      

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