Calculate the molar solubility of Ni(OH) in 0.10 M NaOH. The solubility product of Ni(OH) is 2 × 10 — NEET Chemistry Past Papers Chemistry Question
Question
Calculate the molar solubility of Ni(OH) in 0.10 M NaOH. The solubility product of Ni(OH) is 2 × 10 . (A) 2 × 10 M (B) 3.2 × 10 M (C) 5 × 10 M (D) 3 × 10 M 8 2 2 3 HI −−−−−→ One equi 2 3 2 2 3 2 2 3 2 2 3 2 2 2 2 2 3 w (s) 2 2 3(s) total (s) Na+ (aq) + Cl− (aq) (s) Na+ (g) + Cl− (g)
Answer: A
💡 Solution & Explanation
0 (s) (g) 2(g) 1 2 2(g) 2 (ℓ) 2 2 –15 –13 –8 –5 –17 SPACE FOR ROUGH ALLEN NEET
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