See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

p = 1mm, N = 100 Least count, mm 01 .0 100 mm 1   N P C The instrument has a positive zero error mm 04 .0 01 .0 4        NC e Main scale reading is 2 × (1 mm) = 2 mm Circular scale reading is 67 (0.01) = 0.67 mm  observed reading is mm 67 .2 67 .0 2 0    R So true reading = R0 – e = 2.63 mm AITS-CRT-IV-PCM(Sol.)-JEE(Main)/22 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 9 Chemistry PART – B SECTION – A