In the Claisen-Schmidt reaction to prepare, dibenzalaceone from 5.3 g of benzaldehyde, a total of 3. — JEE Mains Chemistry Past Papers Chemistry Question
Question
In the Claisen-Schmidt reaction to prepare, dibenzalaceone from 5.3 g of benzaldehyde, a total of 3.51 g of product was obtained. The percentage yield in this reaction was ___________%.
Answer: .
💡 Solution & Explanation
2Ph–CHO + CH3–C–CH3 O NaOH Ph–CH=CH–C–CH=CH–Ph O Mole = 106 . = 0.05 05 . × 234 = 5.85 gm % yield = mole l Theoretica mole Actual = weight l Theoretica weight Actual = 60% | JEE(Main) 2025 | DATE : 29-01-2025 (SHIFT-2) | PAPER-1 | CHEMISTRY PAGE # 7
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes