AlCl3 + 3NaOH -> Al(OH)3↓ + 3NaCl — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

Step 1: Aluminum chloride (AlCl3) and sodium hydroxide (NaOH) are highly soluble in water. Step 2: Mixing these solutions leads to the combination of aluminum ions and hydroxide ions to form insoluble gelatinous aluminum hydroxide, Al(OH)3↓. Step 3: Therefore, this is classified as a precipitate formation reaction (type A), corresponding to option (a).