There are five species P, Q, R, S and T. Spectroscopical analysis shows that P, Q and R are homonuclear diatomic species and have their bond order 2.5, 1.5 and 2.5 respectively and rest two species S

Question

There are five species P, Q, R, S and T. Spectroscopical analysis shows that P, 
Q and R are homonuclear diatomic species and have their bond order 2.5, 1.5 and 
2.5 respectively and rest two species S and T are heteronuclear diatomic species
and have bond order 3 and 2 respectively. All homonuclear diatomic species are 
paramagnetic and all heteronuclear diatomic species are diamagnetic in nature. 
P, R, S and T are monovalent positive ion and Q is monovalent negative ion :

Prashant Kotian · Accepted Answer

Correct answer: C. Step 1: Determine the number of π-bonds in each thionic/sulfur oxyacid species by drawing their Lewis structures to satisfy octets/valencies (S exhibits variable valency up to 6). Step 2: Calculate the π-bonds: (II) H2S2O3 has 2 π-bonds; (III) H2S2O5 has 3 π-bonds; (I) H2S2O6 has 4 π-bonds. Step 3: Order the compounds by increasing number of π-bonds: II (2) < III (3) < I (4), which corresponds to option (c).

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