An ideal gas is initially at temperature T and volume V. Its volume increases by ΔV due to an increase in temperature of ΔT, pressure remaining constant. The quantity δ = ΔV/(V × ΔT) varies with tempe

Question

An ideal gas is initially at temperature T and volume V. Its volume increases by ΔV due to an increase in temperature of ΔT, pressure remaining constant. The quantity δ = ΔV/(V × ΔT) varies with temperature as

Prashant Kotian · Accepted Answer

Correct answer: C. δ = ΔV/(VΔT) = (nRΔT/P)/(VΔT) = nR/(PV) = 1/T. δ ∝ 1/T → decreasing hyperbola.

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