At 90°C, the hydronium ion concentration in pure water is 10^-6 M. If 100 ml of 0.5 M - solution is mixed with 250 ml of 0.2 M - solution at 90°C, pH of the resulting solution will be

Question

At 90°C, the hydronium ion concentration in pure water is 10^-6 M. If 100 ml of 0.5 M - $NaOH$ solution is mixed with 250 ml of 0.2 M - $HNO_3$ solution at 90°C, pH of the resulting solution will be

Prashant Kotian · Accepted Answer

Correct answer: B. At 90°C, neutral pH = 6.0 (since [H+] of pure water = 10^-6). Moles OH- = 0.1 * 0.5 = 50 mmol. Moles H+ = 0.25 * 0.2 = 50 mmol. Complete neutralization occurs, giving neutral NaNO3 solution. pH of neutral solution at 90°C = 6.0.

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