A quantity of 10 g of a gas at 1 atm pressure is cooled from 273°C to 273 K keeping its volume const — States of Matter and Gaseous State Chemistry Question
Question
A quantity of 10 g of a gas at 1 atm pressure is cooled from 273°C to 273 K keeping its volume constant, the final pressure of the gas will be
Answer: B
💡 Solution & Explanation
At constant volume: P1 / T1 = P2 / T2. Given: P1 = 1 atm, T1 = 273°C = 546 K, T2 = 273 K. P2 = P1 * (T2 / T1) = 1 * (273 / 546) = 0.5 atm.
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