Correct answer: 00014.06. 1 2 2 1 1 a eV E 3 5         1 225 E a eV 16  x = 14.06

See image | AITS & Test Series — Chem-Mantra

AITS & Test SerieshardNUMERICAL

Question

See image

Answer: 00014.06

💡 Solution & Explanation

1 2 2 1 1 a eV E 3 5         1 225 E a eV 16  x = 14.06

💬

Still have doubts about this question?

Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry