The complex with a maximum number of stereoisomers is : — Coordination Compounds Chemistry Question

💡 Solution & Explanation

Step 1: Calculate the stereoisomers (geometrical + optical) of each option: [PtCl3(C2H4)]^- is square planar and has only 1 form; [CuBr2Cl2]^2- is tetrahedral and has only 1 form; [Co(C2O4)3]^3- has 0 geometrical isomers but is chiral, having d- and l- optical isomers (2 stereoisomers). Step 2: [Cr(NH3)2(en)2]^3+ (type [MA2(XX)2]) has two geometrical isomers: cis and trans. The trans isomer is achiral (1 form), while the cis isomer is chiral and exists as a pair of enantiomers (d- and l- forms). Step 3: This yields a total of 3 stereoisomers for [Cr(NH3)2(en)2]^3+, which is the maximum among the choices, matching option (d).