Correct answer: A. Let ˆ ˆ ˆ r x yj zk     x + y + 4z  14; x, y, z  N Number of triplets (x, y, z) = 1 + 6C4 + 10C8 = 61.

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AITS & Test SerieshardMCQ SINGLE

Question

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Answer: A

💡 Solution & Explanation

Let ˆ ˆ ˆ r x yj zk     x + y + 4z  14; x, y, z  N Number of triplets (x, y, z) = 1 + 6C4 + 10C8 = 61.

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