Data given for the following reaction is as follows : FeO(s) + C(graphite) Fe(s) + CO(g) Substance fHº (kJ mol–1) Sº (J mol–1 K–1) FeO(s) –266.3 57.49 C(graphite) 5.74 Fe(s) 27.28 CO(g) –110.5 197.6 T

Question

Data given for the following reaction is as follows : FeO(s) + C(graphite) Fe(s) + CO(g) Substance fHº (kJ mol–1) Sº (J mol–1 K–1) FeO(s) –266.3 57.49 C(graphite) 5.74 Fe(s) 27.28 CO(g) –110.5 197.6 The minimum temperature in K at which the reaction becomes spontaneous is _______ . (Integer answer) fuEufyf[kr vfHkfØ;k ds fy, % FeO(s) + C(graphite) Fe(s) + CO(g) inkFkZ fHº (kJ mol–1) Sº (J mol–1 K–1) FeO(s) –266.3 57.49 C(graphite) 5.74 Fe(s) 27.28 CO(g) –110.5 197.6 ftl U;wure rki (K esa) ij ;g vfHkfØ;k Lor% izofrZr gks tkrh gS] og gS _______ A (fudVre iw.kk±d esa)

Prashant Kotian · Accepted Answer

Correct answer: ..          S H T o o min           ) CO ( H ) Fe ( H H f f rxn o ] 3 . [ ] . 0 [      = 155.8 kJ/mol        ) CO ( S ) Fe ( S S o o rxn o  ) C ( S ) FeO ( S ) graphite ( o o    = [27.28 + 197.6] – [57.49 + 5.74] = 161.65 J/mol-K K . K mol / J . mol / J 8 . T min      964 K (nearest integer)

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