At a particular temperature and at a pressure of 1 atm, the mass and volume of O₃ that can be dissolved in 1 L of H₂O is 'm' gram and 'V' ml, respectively. Assuming that the solution obeys Henry's law

Question

At a particular temperature and at a pressure of 1 atm, the mass and volume of O₃ that can be dissolved in 1 L of H₂O is 'm' gram and 'V' ml, respectively. Assuming that the solution obeys Henry's law, the mass and volume of O₃ dissolved in 2 L of water at the same temperature and at 5 atm, will be

Prashant Kotian · Accepted Answer

Correct answer: C. Mass dissolved ∝ P × V_solvent → mass = m × 5 × 2 = 10m g. V_gas = nRT/P; since n ∝ P, V_gas is independent of pressure. For 2 L solvent: volume = 2V ml. Hence 10m gram, 2V ml.

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