See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

  2 3 2 2 Li CO s Li O s CO 1 mole       2 3 2 2 3 2 Na CO .10H O s Na CO s 10H O 2 moles     Required answer = 44 + 180 × 2 = 44 + 360 = 404 g.