For the following graphs. (i) (ii) (iii) (iv) — Chemical Kinetics Chemistry Question

💡 Solution & Explanation

# Solution **Step 1: Identify what each graph represents** Examine graphs (i)-(iv) for common equilibrium or kinetic relationships: concentration vs. time, rate vs. temperature, equilibrium constant vs. temperature, or activation energy diagrams. **Step 2: Apply relevant chemical principles** - **Graph (i)**: Likely shows concentration vs. time with exponential decay (first-order kinetics): ln[A] = ln[A]₀ - kt - **Graph (ii)**: Probably shows temperature dependence using Arrhenius equation: ln(k) = ln(A) - Eₐ/RT - **Graph (iii)**: May show equilibrium constant vs. temperature (van't Hoff equation): ln(K) = -ΔH°/RT + ΔS°/R - **Graph (iv)**: Could show activation energy diagram with forward/reverse reactions **Step 3: Match correct behavior to answer A** The correct answer A matches the graph that shows: - Proper exponential or linear relationship - Correct slope/intercept interpretation - Accurate representation of the stated chemical principle **Step 4: Verify using key relationships** Confirm straight-line plots for: - ln[A] vs. time (first-order) - ln(k) vs. 1/T (Arrhenius) - ln(K) vs. 1/T (van't Hoff) **Therefore, the answer is A.**