XeF6 dissolves in anhydrous HF to give a good conducting solution which contains: — p Block Elements Chemistry Question

💡 Solution & Explanation

Step 1: Analyze the interaction of xenon hexafluoride (XeF6) with anhydrous hydrogen fluoride (HF) solvent. Step 2: XeF6 acts as a fluoride donor to the auto-ionizing HF solvent system, participating in a fluoride transfer reaction: XeF6 + 2HF <=> [XeF5]+ + [HF2]-. Step 3: This ionization creates a highly conducting solution containing the [XeF5]+ cation and the [HF2]- anion, matching option (b).