What is the change in internal energy when a gas contracts from 325 ml to 125 ml at a constant pressure of 2 bar, while at the same time being cooled by removing 124 J heat?

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Question

Prashant Kotian · Accepted Answer

Correct answer: B. w = -P * Δ V = -2 * 10^5 Pa * (125 - 325) * 10^-6 m3 = +40 J. Heat removed q = -124 J. Δ U = q + w = -124 + 40 = -84 J.

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