The excitation energy of an electron from second orbit to third orbit of a hydrogen-like atom or ion with +Ze nuclear charge is 47.2 eV. If the energy of H-atom in lowest energy state is -13.6 eV, the

Question

The excitation energy of an electron from second orbit to third orbit of a hydrogen-like atom or ion with +Ze nuclear charge is 47.2 eV. If the energy of H-atom in lowest energy state is -13.6 eV, the value of Z is

Prashant Kotian · Accepted Answer

Correct answer: B. ΔE = 13.6 * Z^2 * (1/2^2 - 1/3^2) = 13.6 * Z^2 * (5/36) = 47.2 eV => Z^2 = (47.2 * 36) / (13.6 * 5) = 25 => Z = 5.

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